[(2+8)/2, (5 +3)/2] = (10/2, 8/2) = (5, 4) The coordinates of the midpoint of (2, 5) and (8, 3) are (5, 4).
(3-5)/(8-2) = -2/6 = -1/3 The slope of the line is -1/3. To find this slope, you have to reduce 2/6 to its lowest terms, 1/3, since both 2 and 6 are evenly divisible by 2.
(3-5)/(8-2) = -2/6 = -1/3 The slope of the line is -1/3. To find this slope, you have to reduce 2/6 to its lowest terms, 1/3, since both 2 and 6 are evenly divisible by 2.
The negative reciprocal of -1/3 is 3 because 3/1 is the reciprocal of 1/3 and the sign has been changed from negative to positive.
3 –> y = mx + b = y = 3x + b
3 –> y = mx + b = y = 3x + b
(5, 4) —> y = 3x + b = 4 = 3(5) + b = 4 = 15 + b
4 = 15 + b = -11 = b b = -11
y = mx + b y = 3x - 11 The equation for the perpendicular bisector of the points (2, 5) and (8, 3) is y = 3x - 11.
